According to the given information, it is required to find the volume of the solid bounded by elliptic cylinder and the planes. 4x^2 + z^2 = 4 and the planes y = 0 and y = z + 2 Now find the limit and evaluate the integral. y limit is form 0 to z + 2 z limit: 4x^2 + z^2 = 4 -> z = +- sqrt(4 - 4x^2) x limit: 4:2 = 4 -> x = +- 1 volume = int_(-1)^(1) int_(-sqrt(4-4x^2))^(sqrt(4-4x^2)) int_(z+2)^(0) dydzdx = int_(-1)^(1) int_(-sqrt(4-4x^2))^(sqrt(4-4x^2)) [y]_(0)^(z+2) dzdx = int_(-1)^(1) int_(-sqrt(4-4x^2))^(sqrt(4-4x^2)) (z+2) dzdx = int_(-1)^(1) [(z^2)/(2) + 2z]_(-sqrt(4-4x^2))^(sqrt(4-4x^2)) dx = int_(-1)^(1) 2 - 2x^2 + 2 sqrt(4-4x^2) - (2 - 2x^2 - 2 sqrt(4-4x^2))dx = int_(-1)^(1) 4sqrt(4-4x^2) dx Solving further: int_(-1)^(1) 4sqrt(4-4x^2) dx = 8 int_(-1)^(1) sqrt(1-x^2) dx = 8 [(x)/(2) sqrt(1-x^2)+ (1)/(2) sin^(-1)(x)]_(-1)^(1) = 8 [(1)/(2) sqrt0 + (1)/(2)sin^(-1) (1)[- (1)/(2) sqrt0 + (1)/(2) sin^(-1)(-1)]] = 8 [(1)/(2)((pi)/(2))-[(1)/(2)(-(pi)/(2))]] = 8 [(pi)/(4) + (pi)/(4)] = 8 ((2pi)/(4)) Volume (V) = 4pi