Find the following probabilities for a standard normal random variable z :
P(-.42
P(-.42
1 Answers
Best Answer
Definitions
Complement rule:
P(A^(C))=P(not A)=1-P(A)
Addition rule for disjoint or mutually exclusive events:
P(A ∪ B)=P(A or B)=P(A)+P(B)
Solution
The probability P(0<= z<= 1.96) is given in the row with z=1.9 and in the column with .06 of the normal probability table in the appendix:
P(0<= z<= 1.96)=0.4750
The probability P(0<= z<= 0.42) is given in the row with z=0.4 and in the column with .02 of the normal probability table in the appendix. The standard normal distribution is symmetric about 0:
P(-0.42<= z<= 0)=P(0<= z<= 0.42)=0.1628
Add the corresponding probabilities:
P(-0.42<= z<= 1.96)=P(0<= z<= 1.96)+P(-0.42<= z<= 0)
=0.4750+0.1628=0.6378