A population is normally distributed with mu = 100 and sigma = 25.
Find the probability that a value randomly selected from this population will have a value less than 95.
1 Answers
Best Answer
From the provided information,
Population mean (mu) = 100
Population standard deviation (sigma) = 25
X sim N (100, 25)
The required probability that a value randomly selected from this population will have a value less than 95 can be obtained as:
P(X<95)=P ((x- mu)/ (sigma)< (95-100)/(25))
=P(Z<-0.2)
=0.4207 (Using standard normal table)
Thus, the required probability is 0.4207.
Population mean (mu) = 100
Population standard deviation (sigma) = 25
X sim N (100, 25)
The required probability that a value randomly selected from this population will have a value less than 95 can be obtained as:
P(X<95)=P ((x- mu)/ (sigma)< (95-100)/(25))
=P(Z<-0.2)
=0.4207 (Using standard normal table)
Thus, the required probability is 0.4207.