A population is normally distributed with mu = 100 and sigma = 25.
Find the probability that a value randomly selected from this population will have a value less than 95.

1 Answers

Best Answer

From the provided information,

Population mean (mu) = 100

Population standard deviation (sigma) = 25

X sim N (100, 25)

The required probability that a value randomly selected from this population will have a value less than 95 can be obtained as:

P(X<95)=P ((x- mu)/ (sigma)< (95-100)/(25))

=P(Z<-0.2)

=0.4207 (Using standard normal table)

Thus, the required probability is 0.4207.

Population mean (mu) = 100

Population standard deviation (sigma) = 25

X sim N (100, 25)

The required probability that a value randomly selected from this population will have a value less than 95 can be obtained as:

P(X<95)=P ((x- mu)/ (sigma)< (95-100)/(25))

=P(Z<-0.2)

=0.4207 (Using standard normal table)

Thus, the required probability is 0.4207.