Find an antiderivative F(x) with F'(x) = f(x) and F(0) = 0. Is there only one possible solution? f(x) = 2x

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An antiderivative F(x) with F'(x)=f(x)

*F'(x)=f(x)**f(x)=2x*Now we take integration*int F'(x)dx= int f(x) dx**F(x)= int 2xdx**F(x)=x^(2)+c*Where c is a constant. Now find out integration constant by using given initial condition F(0)=0*F(0)=(0)^(2)+c**0=c*Thus antiderivative become F(x)=x^(2) hence it is only one possible solution for given initial condition F(0)=0 Result: An antiderivative is F(x) is x^(2) with given initial condition F(0)=0