Find the following probabilities for a standard normal random variable z :
P(-2.16<= z<= .55)
1 Answers
Best Answer
Definitions
Complement rule:
P(A^(C))=P(not A)=1-P(A)
Addition rule for disjoint or mutually exclusive events:
P(A ∪ B)=P(A or B)=P(A)+P(B)
Solution
The probability P(0<= z<= 0.55) is given in the row with z=0.5 and in the column with .05 of the normal probability table in the appendix:
P(0<= z<= 0.55)=0.2088
The probability P(0<= z<= 2.16) is given in the row with z=2.1 and in the column with .06 of the normal probability table in the appendix. The standard normal distribution is symmetric about 0:
P(-2.16<= z<= 0)=P(0<= z<= 2.16)=0.4772
Add the corresponding probabilities:
P(-2.16<= z<= 0.55)=P(0<= z<= 0.55)+P(-2.16<= z<= 0)
=0.2088+0.4846=0.6934