Step 1 Given that: A pole has two wires attached to it, one on side forming two right triangles as shown, From the figure, Length of pole = OB ∠ OAB = 41° ∠ OBA = 90° AB = 34 ft length of wire 1= OA Step2 Part A To calculate the length of pole, In △ OAB, (Perpendicular)/(Base) =tan (41°) (OB)/(AB) = tan (41°) OB = AB * tan(41°) =34 * tan (41°) = 29.56 ft Hence the poll is 29.56 ft tall Step3 Part B To calculate the length of wire 1, Apply Pythagoras theorem in triangle OAB, In △ OAB, (OA)^(2) = (OB)^(2) + (AB)^(2) =(29.56)^(2) +(34)^(2) = 873.7936 + 1156 (OA)^(2) = 2029.7936 OA =sqrt(2029.7936) OA = 45.05 ft Hence wire 1 is 45.05 ft long