GeometrySuppose that a and b are integers
4 weeks ago
Suppose that a and b are integers, a ≡ 11(mod 19), and b ≡ 3(mod 19). Find the integer c with 0 <= c <= 18 such that c ≡ 7a+3b(mod 19)
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beckyandersonson Staff answered 4 weeks ago
Definitions Division algorithm Let a be an integer and d a positive integer. Then there are unique integers q and r with 0 <= r < d such that a=dq+r q is called the quotient and r is called the remainder q=a div d r=a mod d Theorem 5 Let m be a positive integer. If a ≡ b(mod m) and c ≡ d(mod m), then a+c ≡ b+d(mod m) and ac ≡ bd(mod m). Solution a=11(mod 19) b ≡ 3(mod 19) 0 <= c <= 18 Use theorem 5: c ≡ 7a+3b(mod 19) =7*11+3*3(mod 19) =77+9(mod 19) =86(mod 19) =10(mod 19) We then obtain c=10 with 0 <= c <= 18.
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